Third period has a quiz tomorrow, but second period decided to put theirs off until Thursday. At any rate, the quiz will include:
1. Be able to graph parametric equations, finding the correct values for t, and stating the domain and range of parametric functions. (Ex. Given x = 3/(t-2) and y = sin (t), the t values must go from 0 to 2pi to locate all possible values of y, but should contain all reals except 2 to get all the values for x. The x-values of this function would be all reals except 0 and the y-values will be [-1, 1].)
2. Be able to locate points on parametric equations given t-values, x-values or y-values. (Ex. Given the above parametric equations, find the point when t = 3 (3, .1411), the y-intercept (There isn't one) and one of the x-intercepts ( -3/2, 0).)
3. Be able to eliminate the parameter. (Ex. Given the above equations, we could solve the x equation for t, getting t = 3/x +2 or (2x+3)/x. Then sub that into the y equation, leaving: y = sin ((2x + 3)/x). )
4. Write parametric equations of lines, circles, parabolas, ellipses and hyperbolas (especially using trig functions for circles, ellipses and hyperbolas).
5. Set up and solve applications involving circular motion and objects affected by gravity.
Speaking of applications, here is problem #10 from the worksheet today.
A) xChrissy = 40(5280/3600)tcos 29o and yChrissy = 2.5 + 40(5280/3600)tsin 29o - 16t2 . Meanwhile, xKatie = 60 - 35(5280/3600)tcos 38o and yKatie = 3 + 35(5280/3600)tsin 38o - 16t2
B) Find the vertex of each y equation and we find that Chrissy's ball achieved a height f 15.14' at .889 seconds and that Katie's ball reached 18.61' at .9876 seconds.
C) At t = .6529, the balls are 2.566' from each other. (Graph the distance between them in function mode.)
D) It would be difficult for either girl to return the other's ball, but it might be possible. Although after 1.169 sec. (when Chrissy's ball is 60' away), it is 13.88' off the ground, when t = 1.6 seconds, the ball is only 7' off the ground, so if Katie can run 22 feet back in 1.6 seconds, she can return Chrissy's ball. Similarly, after 1.483 seconds (when Katie's ball is where Chrissy is), the ball is 14.68' off the ground, when t = 1.9, the ball is only 5.28' and only 16.86 feet back, so if Chrissy can run 17' in 1.9 seconds she can return Katie's ball.